True
Let two consecutive numbers be x and (x + 1).
Then square of these numbers are x2 and (x + 1)2.
Difference of squares of these consecutive numbers = (x + 1)2 – x2
= x2 + 1 + 2x – x2 [(a + b)2 = a2 + b2 + 2ab)]
= 2x + 1
= x + x + 1
= (x) + (x + 1)
= sum of the two consecutive numbers x and x+1
Thus, difference of squares of two consecutive numbers = sum of the same consecutive numbers.