Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
24.8k views
in Algebraic Expressions by (50.4k points)
closed by

State whether the statements are true (T) or false (F)

The value of p for 512 – 492 = 100 p is 2.

1 Answer

+1 vote
by (49.9k points)
selected by
 
Best answer

True

Solving for p,

(51)2 – (49)2 = 100p

⇒ (50 + 1)2 – (50 – 1)2 = 100p [∵, 51 = 50 + 1 & 49 = 50 – 1]

⇒ (2500 + 1 + 100) – (2500 + 1 – 100) = 100p [∵, (a + b)2 = a2 + b2 + 2ab and (a – b)2 = a2 + b2 – 2ab)]

⇒ 2500 + 1 + 100 – 2500 – 1 + 100 = 100p

⇒ 200 = 100p

⇒ 100p = 200

⇒ p = 200/100 = 2

The value of p is 2.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...