Let the salary for the three types of staff A, B and C be Rs. x, Rs.y and Rs.z respectively.
According to the problem we have,
4x + 2y + 3z = 4900
3x + 3y + 2z = 4500
4x + 3y + 4z = 5800

Hence the salary for staff A is Rs. 700 for staff B is Rs. 600 and staff C is Rs. 300.