If A = [(1,tan θ/2),(-tan θ/2,1)] and AB = I2, then B = ... (a) (cos^2 θ/2)A (b) (cos^2 θ/2)A^T (c) (cos^2 θ)I (d) (sin^2 θ/2)A

Question

If A = \(\begin{bmatrix} 1 &tan(θ/2) \\[0.3em] -tan(θ/2)&1 \\[0.3em] \end{bmatrix}\) and AB = I₂, then B = ...

(a) (cos² θ/2)A

(b) (cos² θ/2)A^T

(c) (cos² θ)I

(d) (sin² θ/2)A

Answer 1

(b) (cos² θ/2)A^T

Given