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If (1 - i/1 + i) is a root of the equation ax^2 + bx + 1 = 0. where a, b are real, then (a, b) is ... (a) (1 ,1) (b) (1, -1) (c) (0, 1)

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If (1 - i/1 + i) is a root of the equation ax2 + bx + 1 = 0. where a, b are real, then (a, b) is ...

(a) (1 ,1) 

(b) (1, -1) 

(c)  (0, 1) 

(d) (1, 0)

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(d) The answer is (1 ,0)

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