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Integrate ∫(e^2x - 1)/(e^2x + x) dx

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Integrate ∫(e2x - 1)/(e2x + x) dx

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1 Answer

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Best answer

Dividing numerator and denominator by ex, we get

∫(ex - e-x)/(ex + e-x)dx

Now d/dx(ex + e-x) 

= ex - e-x 

= log(ex + e-x) +c

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