Question

Find the area of the region lying in the first quadrant bounded by the region y = 4x² , x = 0, y = 0 and y = 4. 

Answer 1

The given parabola is y = 4x² 

x² = y/4

comparing with the standard form x² = 4ay 

4a = 1/4 ⇒ a = 1/16

The parabola is symmetric about y-axis 

We require the area in the first quadrant.