To find y = f(x) at x = 2.8 from the given table.
We use Newton’s backward interpolation formula since the required value is near the end of the table.
2.8 = 3 + (n)1
n = 2.8 – 3 = -0.2
The difference table given below
y = 34 – 4.6 – 1.12 – 0.288
y = 27.992
Hence the value of f(x) at x = 2.8 is 27.992