Question

Calculate the number of unpaired electrons in Ti³⁺ Mn²⁺ and calculate the spin only magnetic moment.

Answer 1

Ti³⁺

Ti (Z = 22). Electronic configuration [Ar] 3d² 4s² 

Ti³⁺ – Electronic configuration [Ar] 3d¹

So, the number of unpaired electrons in Ti³⁺ is equal to 1.

Spin only magnetic moment of Ti³⁺ = \(\sqrt1(1+2)\) = \(\sqrt3\) = 1.73 µ_B

Mn²⁺ :

Mn (Z = 25) Electronic configuration [Ar] 3d⁵4s²

Mn²⁺ – Electronic configuration [Ar] 3d⁵

Mn²⁺ has 5 unpaired electrons. 

Spin only magnetic moment of Mn²⁺ \(\sqrt{5(5+2)}\) = \(\sqrt35 \) = 5.91µ_B