According to the question,
We have to construct a triangle if its perimeter is 10.4 cm and two angles are 45° and 120°
Steps of construction:
1. Draw XY = 10.4 cm.
2. Draw ∠LXY = 45o and ∠MYX =120o
3. Draw angle bisector of ∠LXY.
4. Draw angles bisector of ∠MYX such that it meets the angle bisector of ∠LXY at point A.
5. Draw the perpendicular bisector of AX such that it meets XY at B.
6. Draw the perpendicular bisector of AY such that it meets XY at C.
7. Join AB and AC.
Thus, ABC is the required triangle.
