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Show that the value in the conclusion of the mean value theorem for (i) f(x) = 1/x on a closed interval of positive numbers [a,b] is √ab

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Show that the value in the conclusion of the mean value theorem for

(i) f(x) = 1/x on a closed interval of positive numbers [a,b] is √ab

(ii) f(x) = Ax2 + Bx + C on any interval [a,b] is (a + b)/2

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1 Answer

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Best answer

(i) f(x) = 1/x

Now 

(ii) f(x) = Ax2 + Bx + C

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