Question

A deuteron and an alpha particle are accelerated with the same potential. Which one of the two has 

(i) greater value of de Broglie wavelength associated with it and 

(ii) less kinetic energy? Explain.

Answer 1

(i) Using de-Broglie wavelength formula, the dueteron and alpha particle are accelerated with same potential. So, both their velocities are same.

(ii) For same potential of acceleration, KE is 

directly proportional to the ‘q’ 

Charge of duetron is +e 

Charge of alpha is +2e 

So, K_d =\(\frac{K_a}{2}\) 

Charge of alpha particle is more than the duetron.