Given: ∆ABC ∼ ∆DFE,
As ∆ABC ∼ ∆DFE so, by the property of Corresponding angles of similar triangles,
We have,
∠A = ∠D = 30° (Corresponding angles)
∠C = ∠E = 50° (Corresponding angles)

We know that sum of angles of a triangle = 180°
So,
∴ ∠B = ∠F = 180°- (30° + 50°) = 100°
Also Given,
AB = 5 cm,
AC = 8 cm and
DF = 7.5 cm

Hence,
DE = 12 cm, and ∠F = 100°