Question

If NaCI is doped with 10² mol percentage of strontium chloride, what is the concentration of cation vacancy?

Answer 1

We know that two Na⁺ ions are replaced by each of the Sr²⁺ ions while SrCl² , is doped with NaCI. But in this case, only one lattice point is occupied by each of the Sr²⁺ ions and produce one cation vacancy. 

Here 10^-2 mole of SrCI₂ , is doped with 100 moIes of NaCI. Thus, cation vacancies produced by NaCi = 10^-2 mol. Since, 100 moles of NaCl produces cation vacancies after doping = 10^-2 mol. Therefore, I mole of NaCl will produce cation vacancies after doping