(B) 3/4
According to the question,
cos A = 4/5 …(1)
We know,
tan A = sinA/cosA
To find the value of sin A,
We have the equation,
sin2 θ +cos2 θ =1
So, sin θ = √ (1-cos2 θ)
Then,
sin A = √ (1-cos2 A) …(2)
sin2 A = 1-cos2 A
sin A = √(1-cos2 A)
Substituting equation (1) in (2),
We get,
Sin A = √(1-(4/5)2)
= √(1-(16/25))
= √(9/25)
= ¾
Therefore,
