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in Semiconductor Electronics by (48.7k points)
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An NPN BJT having reverse saturation current IS = 10-15 A is biased in the forward active region with VBE = 700 mV and the current gain (β) may vary from 50 to 150 due to manufacturing variations. What is the maximum emitter current (in μA)

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Best answer

IS = 10-15

VBE = 700 

VT = 25 mV 

β range from 50 to 150

IE will be maximum when β is 50 

 IE = 1475 μA

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