Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.6k views
in Ordinary Differential Equations by (49.3k points)
closed by

Show that y = ae-3x + b, where a and b are arbitrary constants, is a solution of the differential equation (d2y/dx2) + 3(dy/dx) = 0 

1 Answer

+1 vote
by (47.2k points)
selected by
 
Best answer

y = ae-3x + b (a and b are arbitrary constants) ... (1) 

Differentiating with respect to x 

dy/dx = - 3ae-3x

Differentiating again with respect to x 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...