Question

Calculate the 

1. hydrolysis constant 

2. degree of hydrolysis and 

3. pH of 0.05M sodium carbonate solution pK_a for HCO^-₃ is 10.26

Answer 1

1. Hydrolysis constant

Given

K_w = 1 x 10^-14

c = 0.05 M

PK_a = 10.26 

K_a = – log K_a 

K_a = antilog of (- pK_a) 

K_a = antilog of (- 10.26)

K_a = 5.49 x 10^-11

h = 6.034 x 10^-2 

2. Degree of hydrolysis