According to the question,
cos(α + β) = 4/5 …(i)
We know that,
sin x = √(1 – cos2x)
Therefore,
sin (α + β) = √(1 – cos2(α + β))
⇒ sin (α + β) = √(1 – (4/5)2) = 3/5 …(ii)
Also,
sin(α – β) = 5/13 {given} …(iii)
we know that,
cos x = √(1 – sin2x)
Therefore,
cos (α – β) = √(1 – sin2(α – β))
⇒ cos (α – β) = √(1 – (5/13)2) = 12/13 …(iv)
Therefore,
tan 2α = tan (α + β + α – β)
We know that,

Hence, tan 2α = 56/33