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The emf of the following cell at 25°C is equal to 0.34v. Calculate the reduction potential of copper electrode.

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The emf of the following cell at 25°C is equal to 0.34v. Calculate the reduction potential of copper electrode. 

Pt(s) | H2(g,1atm) | H+ (aq,1M) || Cu2+ (aq,1M) | Cu(s)

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SHE Value is zero 

Ecell° = ER° – EL° 

= 0.34 – 0 = 0.34V 

The reduction potential of copper electrode = 0.34V

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