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Solve the linear differential equation: (dy/dx) + (3y/x) = 1/x^2, given that y = 2 when x = 1

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Solve the linear differential equation:

(dy/dx) + (3y/x) = 1/x2, given that y = 2 when x = 1

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(dy/dx) + (3y/x) = 1/x2

This is a linear differential equation of the type (dy/dx) + Py = Q

2x3y = x2 + 3

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