Question

A bomb of 10 kg at rest explodes into two pieces of mass 4 kg and 6 kg. if the velocity of 4 kg mass is 6 ms^-1 then the velocity of 6 kg is –

(a) – 4 ms^-1 

(b) – 6 ms^-1 

(c) – 24 ms^-1 

(d) – 2.2 ms^-1

Answer 1

(a) -4ms^-1

According to law of conservation of momentum m₁v₁ + m₂v₂ = 0

v₂ = -\(\frac{m_1v_1}{m_2}\) = -\(\frac{4 \times 6}{6}\) = -4ms^-1