(3) T, T, F
(p ∧ q) → (~q \(\lor\) r) = false
when (p ∧ q) = T
and (~q \(\lor\) r) = F
So (p ∧ q) = T is possible when p = q = true
\(\therefore\) ~q = False (q = true)
So (~q \(\lor\) r) = False is possible if r is false
\(\therefore\) p = T, q = T, r = F