Question

A cricket ball of mass 0.15 kg is thrown vertically up by a bowling machine so that it rises to a maximum height of 20 m after leaving the machine. If the part pushing the ball applies a constant force F on the ball and moves horizontally a distance of 0.2 m while launching the ball, the value of F (in N) is (g = 10 ms^–2) ____.

Answer 1

150.00

Initial velocity \(V_0^2\) = 2gh

⇒ V₀ = √(2 X 10 X 20) 

= 20 m/s 

Now work done by the machine.

⇒ F = 150