Question

Two charged thin infinite plane sheets of uniform surface charge density σ₊ and σ_–, where |σ₊| > |σ_–|, intersect at right angle. Which of the following best represents the electric field lines for this system?

Answer 1

Answer is (4) 

Thin infinite uniformly charged planes produces uniform electric field.

And as positive charge density is bigger in magnitude so its field along Y direction will be bigger than field of negative charge in X direction.

Answer 2

Correct option is (4)

The electric field produced due to a uniformly charged infinite plane is,

\(E=\frac{σ }{2ε_0}\) = constant

So, option (2) and (4) are wrong.

∵ |σ₊| > |σ_-|

Hence, its field along y^- direction will be bigger than field of ^-ve charge density σ^- in x^- direction.