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If |x + 2| ≤ 9, then x belongs to (a) (-∞, -7) (b) [-11, 7] (c) (-∞, -7) ∪ [11, ∞)

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If |x + 2| ≤ 9, then x belongs to 

(a) (-∞, -7) 

(b) [-11, 7] 

(c) (-∞, -7) ∪ [11, ∞) 

(d)(-11, 7)

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1 Answer

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Best answer

(b) [-11, 7]

-x – 2 ≤ 9 x + 2 ≤ 9 

-x < 9 + 2 = 11 x ≤ 9 – 2 = 7 

⇒ x ≥ -11 

So x ∈ [-11, 7]

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