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Evaluate: ∫ tan^2 x sec^4 x dx

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Evaluate:

∫ tan2 x sec4 x dx

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1 Answer

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Given; ∫tan2 x sec4 x dx

=∫ tan2 x sec2 x (1+ tan2 x) dx

Let; tan x = y

⇒ sec2 x dx = dy

=∫y2+y4 dy

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