Question

The area of the region bounded by the curve x² = 4y and the straight line x = 4y – 2 is.

A. 3/8 sq units

B. 5/8 sq units

C. 7/8 sq units

D. 9/8 sq units

Answer 1

Given;

The curve x² = 4y and the straight line x = 4y – 2

By substituting for 4y;

⇒ x = x² − 2

⇒ x² − x − 2 = 0

⇒ (x + 1) (x − 2) = 0

∴ x = −1, 2.

Required area