No. of cards = 52 : In that number of aces = 4
No. of cards needed = 5
In that 5 cards number of aces needed = 3
So the 3 aces can be selected from 4 aces in 4C3 = 3C1 = 4 ways
So the remaining = 5 – 3 = 2
This 2 cards can be selected in 48C2 ways
48C2 = (48 x 47)/(2 x 1) = 1128 ways
∴ No. of ways in which the 5 cards can be selected = (48C2)(4C3)
= (48 x 47)/(2 x 1) = 4 = 4512