How many molecules are present in 32 g of methane? (a) 2 x 6.23 x 10^23 (b) 6.023 x 10^​​​​​​​23 (c) 6.023 x 10​​​​​​​^23

Question

How many molecules are present in 32 g of methane? 

(a) 2 x 6.023 x 10²³ 

(b) 6.023 x 10²³  

(c) 6.023 x 10²³ 

(d) 3.011 x 10^{​​​​​​​23} 

Answer 1

(a) 2 x 6.023 x 10²³ 

Methane (CH₄) – Molar mass = 12 + 4 = 16g. 

16 g contains 6.023 x 10²³ molecules. 

∴ 32 g of methane will contain =\(\frac{6.023\times10^{23}}{16}\) x 32²

= 2 x 6.023 x 10²³