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Calculate the oxidation number of underlined elements in the following. 

1. KMnO4 

2. Cr2O72-

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Best answer

1. KMnO4 

1(+1) + x + 4(-2) = 0 

x – 7 = 0 

∴ x = + 7 

Oxidation state of Mn = +7

2. Cr2O72-

2x + 7(-2) = -2 

2x – 14 = – 2 

2x = +12 

∴ x = + 6 

Oxidation state of Cr = +6.

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