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How much copper can be obtained from 100 g of anhydrous copper sulphate?

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Anhydrous copper sulphate = CuSO4 

Molecular mass of CuSO4 = 63.5 + 32 + (16 x 4) 

= 63.5 + 32 + 64 

= 159.5 g 

159.5 g of CuSO4 contains 63.5 g of copper. 

∴ 100 g of CuSO4 contains \(\frac{6.35}{159.5}\) x 100 = 0.39811 x 100 = 39.81 g of Copper.

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