The image of the point P (1, 2) will be P’ (1, -2).
Since ∠OAP = ∠XAQ (angle of inches = angle of reflection)
So ∠OAP’ = ∠XAQ = a (Vertically opposite angles)
⇒ P’, A, Q lie on a same line.
Now equation of the line P’, Q is [where P’ = (1, -2), Q = (5, 3)]
Since we find point of intersection with x axis we put y = 0.
So