Given numbers are 96 and 404.
The prime factorization of 96 and 404 gives:

Here, 22 is the smallest power of the common factor 2.
Therefore, the H.C.F of these two integers is 2 × 2 = 4
25 × 31 × 1011 are the greatest powers of the prime factors 2, 3 and 101 respectively involved in the given numbers.
Now, L.C.M of 96 and 404 is 2 × 2 × 2 × 2 × 2 × 3 × 101 = 9696