Given numbers are 6, 72 and 120
Factorization of 6, 72 and 120

Here, 21 × 31 are the smallest powers of the common factors 2 and 3, respectively.
So, HCF (6, 72, 120) = 2 × 3 = 6
23 × 32 × 51 are the greatest powers of the prime factors 2, 3 and 5 respectively involved in the given three numbers .
LCM of these three integers = 2 × 2 × 2 × 3 × 3 × 5 = 360