Given numbers are 12, 15 and 21
Factorization of 12, 15 and 21

Here, 31 is the smallest power of the common factor 3.
So, HCF (12, 15, 21) = 3
22 × 31 × 51 × 71 are the greatest powers of the prime factors 2, 3, 5 and 7 respectively involved in the given three numbers .
LCM of these three integers = 2 × 2 × 3 × 5 × 7 = 420