Let f(x) = 3x2 – x – 4
By splitting the middle term, we get
f(x) = 3x2 – (4 – 3)x – 4 [∵ – 1 = 3 – 4 and 4×3 = 12]
= 3x2 + 3x – 4x – 4
= 3x(x + 1) – 4(x + 1)
= (3x – 4) (x + 1)
On putting f(x) = 0, we get
(3x – 4) (x + 1) = 0
⇒ 3x – 4 = 0 or x + 1 = 0
x = 4/3 or x = – 1
Thus, the zeroes of the given polynomial 3x2 – x – 4 are – 1 and 4/3.
Verification

So, the relationship between the zeroes and the coefficients is verified.