Let f(x) = 2 x2 – 7x
In this the constant term is zero.
f(x) = 2 x2 – 7x
= x(2x – 7)
On putting f(x) = 0 , we get
x(2x – 7) = 0
⇒ 2x – 7 = 0 or x = 0
x = 7/2 or x = 0
Thus, the zeroes of the given polynomial 2x2 – 7x are 0 and 7/2
Verification

So, the relationship between the zeroes and the coefficients is verified.