Given, pair of equations
ax + 3y = a – 2
and 12x + ay = a
On comparing the given equation with standard form i.e. a1 x + b1y + c1 = 0 and a2 x + b2y + c2 = 0, we get
a1 = a, b1 = 3 and c1 = – (a – 2)
and a2 = 12, b2 = a and c2 = – a
For no solutions,

⇒ a2 = 36
⇒ a = √36
⇒ a = ±6