Given paths traced by the wheel of two trains are
x + 2y – 4 = 0 …(i)
2x + 4y – 12 = 0
⇒ x + 2y – 6 = 0 …(ii)
As we can see that a1 = 1, b1 = 2 and c1 = – 4
and a2 = 1, b2 = 2 and c2 = – 6
∴ Given pair of equations has no solution
Hence, two paths will not cross each other.