Question

Choose the correct statement(s) among the following. 

(A) SnCl₂.2H₂O is a reducing agent. 

(B) SnO₂ reacts with KOH to form K₂[Sn(OH)₆]. 

(C) A solution of PbCl₂ in HCl contains Pb²⁺ and Cl⁻ ions. 

(D) The reaction of Pb₃O₄ with hot dilute nitric acid to give PbO₂ is a redox reaction.

Answer 1

A,B OR A,B,C

(A) SnCl₂.2H₂O is a reducing agent since Sn²⁺ tends to convert into Sn⁴⁺

(C) First group cations (Pb²⁺) form insoluble chloride with HCl that is PbCl₂ however it is slightly soluble in water and therefore lead +2 ion is never completely precipitated on adding hydrochloric acid in test sample of Pb²⁺, rest of the Pb²⁺ ions are quantitatively precipitated with H₂S in acidic medium. 

So that we can say that filtrate of first group contain solution of PbCl₂ in HCl which contains Pb²⁺ and Cl^– 

However in the presence of conc. HCl or excess HCl it can produce H₂[PbCl4] 

So, we can conclude A, B or A,B,C should be answers.

It is not a redox reaction.