
Let,
Side opposite to angle θ = 12k
and Hypotenuse = 13k
where, k is any positive integer
So, by Pythagoras theorem, we can find the third side of a triangle
⇒ (AB)2 + (BC)2 = (AC)2
⇒ (12k)2 + (BCk)2 = (13)2
⇒ 144 k2 + (BC)2 = 169 k2
⇒ (BC)2 = 169 k2 –144 k2
⇒ (BC)2 = 25 k2
⇒ BC =√25 k2
⇒ BC =±5k
But side BC can’t be negative. So, BC = 5k
Now, we have to find the value of cos θ and tan θ
We know that,

Now, tan θ
We know that,
