
1. The hydrocarbon with molecular formula C3H6
(A) is identified as propene, CH – CH = CH2
2. Propene reacts with HBr to form bromopropane
CH3 – CH2 – CH2 Br as (B).

3. 1 – bromopropane react with aqueous potassium hydroxide to give 1 – propanol CH3 – CH2 – CH2 OH as (C).
4. 2 – bromo propane reacts with aqueous KOH to give 2-propanol as (C)

