If f(x) = {(x + 1, when x < 2), (2x - 1, when x ≥ 2) then f ‘(2) is … (a) 0 (b) 1 (c) 2 (d) does not exist

Question

If \(f(x) = \begin{cases} x+1, & \quad \text{when } x<2 \text{ }\\ 2x-1, & \quad \text{when } x≥2 \text{ } \end{cases}\) then f ‘(2) is …

(a) 0 

(b) 1 

(c) 2 

(d) does not exist

Answer 1

(d) does not exist

∴ f‘(2) does not exist