Given: ABCD is a trapezium with AB || CD
and diagonals AB and CD intersecting at O
To find: y
Firstly, we prove that △OAB ~ △ODC
Let △OAB and △ODC
∠AOB = ∠COD [vertically opposite angles]
∠OBA = ∠ODC [∵AB || CD with BD as transversal alternate angles are equal]
∠OAB = ∠OCD [∵AB || CD with BD as transversal alternate angles are equal]
∴ △OAB ~ △ODC [by AAA similarity]
Since triangles are similar. Hence corresponding sides are proportional.

⇒ y = 6 cm