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∫e^-7x sin 5x dx is ... (a) (e^-7x/74) [-7 sin 5x - 5 cos 5x] + c (b) (e^-7x/74) [7 sin 5x + 5 cos 5x] + c (c) (e^-7x/74) [7 sin 5x - 5 cos 5x] + c

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∫e-7x sin 5x dx is ...

(a) (e-7x/74) [-7 sin 5x - 5 cos 5x] + c

(b) (e-7x/74) [7 sin 5x + 5 cos 5x] + c

(c) (e-7x/74) [7 sin 5x - 5 cos 5x] + c

(d) (e-7x/74) [-7 sin 5x + 5 cos 5x] + c

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(a) (e-7x/74) [-7 sin 5x - 5 cos 5x] + c

We know that 

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