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Calculate the entropy change of a process H2O(I) → H2O(g) at 373K. Enthalpy of vaporization of water is 40850 J Mole^-1.

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Calculate the entropy change of a process H2O(I) → H2O(g) at 373K. Enthalpy of vaporization of water is 40850 J Mole-1.

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H2O(I) → H2O(g)

Temperature T = 373 K 

Enthalpy of vapourisation of water = ∆Vvap = 40580 J mol-1

∆S = entropy change = ∆Hvap/Tb = 40850 / 373

∆S(entropy change) = 109.51 J mol-1 K-1

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