Question

The molality of a solution containing 1.8 g of glucose dissolved in 250 g of water is …

(a) 0.2 M 

(b) 0.01 M

(c) 0.02 M 

(d) 0.04 M

Answer 1

(d) 0.04 M

Molality = (Number of moles of solute) / (Weight of solvent (in kg) 

= (1.8/180) / 0.25

= 0.01 / 0.25

= 0.04 M