Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
5.4k views
in Algebra by (48.0k points)
closed by

Graph the following quadratic equations and state their nature of solutions,

(i) x2 + x + 7 = 0

(ii) x2 – 9 = 0

1 Answer

+2 votes
by (47.6k points)
selected by
 
Best answer

(i) Let y = x2 + x + 7

Step 1:

Step 2: Points to be plotted: (-4, 19), (-3, 13), (-2, 9), (-1, 7), (0, 7), (1, 9), (2, 13), (3, 19), (4, 27) 

Step 3: Draw the parabola and mark the co-ordinates of the parabola which intersect with the x-axis.

Step 4: The roots of the equation are the points of intersection of the parabola with the x axis. Here the parabola does not intersect the x axis at any point.

So, we conclude that there is no real roots for the given quadratic equation.

(ii) Let y = x2 – 9 

Step 1:

Step 2: The points to be plotted: (-4, 7), (-3, 0), (-2, -5), (-1, -8), (0, -9), (1,-8), (2, -5), (3, 0), (4, 7) 

Step 3: Draw the parabola and mark the co-ordinates of the parabola which intersect the x-axis.

Step 4: The roots of the equation are the co-ordinates of the intersecting points (-3, 0) and (3, 0) of the parabola with the x-axis which are -3 and 3 respectively. 

Step 5: Since there are two points of intersection with the x axis, the quadratic equation has real and unequal roots. 

∴ Solution{-3, 3}

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...