Question

Which among the following is (are) double displacement reaction(s)?

(i) Pb + CuCl₂→ PbCl₂ + Cu 

(ii) Na₂SO₄ + BaCl₂→ BaSO₄ + 2NaCl 

(iii) C + O₂→ CO₂ 

(iv) CH₄ + 2O₂→ CO₂ + 2H₂O 

A. (i) and (iv) 

B. (ii) only 

C. (i) and (ii) 

D. (iii) and (iv)

Answer 1

The reaction (i) is a type of displacement reaction as Pb displaces Cu and form a new compound PbCl₂

The reaction (ii) is a type of double displacement reaction in which exchange of ions takes place.

The reaction (iii) is a type of combination reaction in which carbon and oxygen are combined together to form a single product that is CO₂ .

The reaction (iv) is a type of exothermic reaction as the burning of natural gas (CH₄ ) releases a large amount of energy